RE: help guys!! (Math related)

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RE: help guys!! (Math related)

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RE: help guys!! (Math related) - 10/2/2008 10:58:08 PM

CodyD

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lol its cool...look at it as two overlapping circles. One created by the fence and the other created by the cow at the very end of the rope. This is more difficult than I thought. Maybe I need to brush up on my geometry.

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Post #: 91

RE: help guys!! (Math related) - 10/2/2008 10:59:10 PM

CodyD

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quote:

ORIGINAL: P360onBugs

k

ill let that stew cody

we will resume this conversation later

Good idea I will report back later if I can figure it out.

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Post #: 92

RE: help guys!! (Math related) - 10/2/2008 11:02:00 PM

OUTLAWED450S

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quote:

ORIGINAL: CodyD

quote:

ORIGINAL: OUTLAWED450S

quote:

ORIGINAL: P360onBugs

you guys want a tough one. here one ive been working on for a while. lets say you have a circular fence with a radius of x. and you tie a horse with a rope to the perminter of the fence. how long must the rope be so he can eat exactly half of the circular lot. express your answer in terms of x(the radius of the circular lot)

i cant figure this one out. it makes me mad.

if it makes it easier lets say the radius of the lot is 100 foot. how long does the rope need to be?

if the yard is a 100 foot circle. the rope has to be 29.32 feet long. give me something hard

Well with the cow tied to one point on the outer edge of a circle with diameter of 100 and radius of 50, 29.32 feet doesn't even allow the cow to reach the middle. There is no way it could eat half the grass in the pen.

your think about him eating half way accros..hes eating in a circle tied to the perimete of the fence if you give him 50 feet he will walk in a circle and eat i all. think of this way. when track runners start they start one ahead of the other but the run the same distance. becase the outer line would be longer if they started side by side.

ok if the radius is 50 foot, off the top of your head you say he needs 25 foot rope to walk around and eat hald of it. but eh outer 25 contains more area than the inner 25 foot.

i told yall i can explain this stuff

< Message edited by OUTLAWED450S -- 10/2/2008 11:04:15 PM >

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Post #: 93

RE: help guys!! (Math related) - 10/2/2008 11:06:31 PM

CodyD

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quote:

ORIGINAL: OUTLAWED450S

quote:

ORIGINAL: CodyD

quote:

ORIGINAL: OUTLAWED450S

quote:

ORIGINAL: P360onBugs

you guys want a tough one. here one ive been working on for a while. lets say you have a circular fence with a radius of x. and you tie a horse with a rope to the perminter of the fence. how long must the rope be so he can eat exactly half of the circular lot. express your answer in terms of x(the radius of the circular lot)

i cant figure this one out. it makes me mad.

if it makes it easier lets say the radius of the lot is 100 foot. how long does the rope need to be?

if the yard is a 100 foot circle. the rope has to be 29.32 feet long. give me something hard

Well with the cow tied to one point on the outer edge of a circle with diameter of 100 and radius of 50, 29.32 feet doesn't even allow the cow to reach the middle. There is no way it could eat half the grass in the pen.

your think about him eating half way accros..hes eating in a circle tied to the perimete of the fence if you give him 50 feet he will walk in a circle and eat i all. think of this way. when track runners start they start one ahead of the other but the run the same distance. becase the outer line would be longer if they started side by side.

ok if the radius is 50 foot, off the top of your head you say he needs 25 foot rope to walk around and eat hald of it. but eh outer 25 contains more area than the inner 25 foot.

i told yall i can explain this stuff

You are looking at it as if he were tied to the center. He is tied to the fence and the point at which he is tied is stationary. The length of the rope will have to be between 50 and 100 feet.

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Post #: 94

RE: help guys!! (Math related) - 10/2/2008 11:07:17 PM

P360onBugs

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do what?. the lenght of the rope has to be more than the radious of the fence.

exactly cody. i was told it is aproximatly 1.16 times the radius of the fence. but thats all i know. lol

< Message edited by P360onBugs -- 10/2/2008 11:09:04 PM >

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Post #: 95

RE: help guys!! (Math related) - 10/2/2008 11:09:40 PM

CodyD

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quote:

ORIGINAL: P360onBugs

do what?. the lenght of the rope has to be more than the radious of the fence.

exactly cody. i was told it is aproximatly 1.16 times the radius of the fence. but thats all i know. lol

Yes. Sounds crazy but yes.

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Post #: 96

RE: help guys!! (Math related) - 10/2/2008 11:10:10 PM

P360onBugs

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you got that number?

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Post #: 97

RE: help guys!! (Math related) - 10/2/2008 11:11:32 PM

OUTLAWED450S

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100 foot circle has an area of 7850 ft2. a 50 foot circle has a area of 1962.5 ft2. so that tells you the inner 25 foot is roughly 4 times less area than the outer half of the circle. so that means you would have to lenghten the rope about 50% more if the was tied to a pole in the middle... if he was tied like the problem states you would need to shorten the rope about 50%.

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Post #: 98

RE: help guys!! (Math related) - 10/2/2008 11:11:42 PM

CodyD

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quote:

ORIGINAL: CodyD

quote:

ORIGINAL: P360onBugs

do what?. the lenght of the rope has to be more than the radious of the fence.

exactly cody. i was told it is aproximatly 1.16 times the radius of the fence. but thats all i know. lol

Yes. Sounds crazy but yes.

Before you edited your post I thought you were asking me if the rope had to be more than the radius.

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Post #: 99

RE: help guys!! (Math related) - 10/2/2008 11:12:54 PM

OUTLAWED450S

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are yall talking about the horse walking around the outer edge eating in a circle far as he can reach.

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Post #: 100

RE: help guys!! (Math related) - 10/2/2008 11:14:08 PM

CodyD

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quote:

ORIGINAL: OUTLAWED450S

are yall talking about the horse walking around the outer edge eating in a circle far as he can reach.

No not walking around the outer edge but being tied to a point on the outer edge.

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Post #: 101

RE: help guys!! (Math related) - 10/2/2008 11:15:40 PM

OUTLAWED450S

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boy i just wasted alot of typing. i think ill work on that one tommorow

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Post #: 102

RE: help guys!! (Math related) - 10/2/2008 11:16:44 PM

CodyD

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quote:

ORIGINAL: OUTLAWED450S

boy i just wasted alot of typing. i think ill work on that one tommorow

HAHA...I wasn't sure what you were doing but you sounded confident anyway.

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Post #: 103

RE: help guys!! (Math related) - 10/2/2008 11:18:03 PM

CodyD

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Give me a little time P360 and I'll see what I can come up with.

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Post #: 104

RE: help guys!! (Math related) - 10/2/2008 11:18:40 PM

P360onBugs

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the horse is inside the fence but tied to the fence. if that makes sense

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Post #: 105

RE: help guys!! (Math related) - 10/2/2008 11:33:52 PM

OUTLAWED450S

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hey bugs what was the model number for that odessy battery in ebay that will fit the ACs

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Post #: 106

RE: help guys!! (Math related) - 10/2/2008 11:35:35 PM

P360onBugs

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pc680. you will not be able to have the tool tray with it. cause it is taller.

man them batteries have gone UP in price. i think mine was like 83 bucks or so.

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motor mods and mud mods.

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Post #: 107

RE: help guys!! (Math related) - 10/2/2008 11:36:48 PM

P360onBugs

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btw. i have some cat axles. shafts and junk. they are pieces but next time we go riding at the lake. you can have them. just pieces but you never know

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Of course my winches work--THEY'RE WARNS aint they?

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Post #: 108

RE: help guys!! (Math related) - 10/3/2008 7:57:47 AM

OUTLAWED450S

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ill take them off your hands. if you dont want them.

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Post #: 109

RE: help guys!! (Math related) - 10/3/2008 8:20:42 AM

P360onBugs

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they are just in my way to tell you the truth. also have a set of stock springs that you can have. if you want.

hey are you going to do any riding this weekend?

if you are would you like to do a short ride at the lake? its not great riding now. but hey its free. lol

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motor mods and mud mods.

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Post #: 110

RE: help guys!! (Math related) - 10/3/2008 9:30:58 AM

OUTLAWED450S

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i cant go this weekend becuase i got rid of my 6" lift and i am waith on the stock supension to come in. and i got a a 2"ift and axle extions and 30 sivlver backs i want to try.

i talk to brad and we will see if he wants to take the prowler.

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Post #: 111

RE: help guys!! (Math related) - 10/3/2008 10:16:19 AM

P360onBugs

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quote:

ORIGINAL: OUTLAWED450S

i cant go this weekend becuase i got rid of my 6" lift

very very smart move. you wont regret that at all. i know i didnt.

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Post #: 112

RE: help guys!! (Math related) - 10/3/2008 10:33:18 AM

OUTLAWED450S

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i think the only other thing i want to is get 4.0s in it.

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Post #: 113

RE: help guys!! (Math related) - 10/3/2008 12:44:01 PM

Big_T

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On you corral problem, I just worked through it in the last 15 minutes and determined that the rope, R, will be 1.158728473 times the radius of the corral.

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Post #: 114

RE: help guys!! (Math related) - 10/3/2008 12:45:49 PM

P360onBugs

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interesing. care to show your formula?

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Post #: 115

RE: help guys!! (Math related) - 10/3/2008 12:56:24 PM

Big_T

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I'll try to get it up later.

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Post #: 116

RE: help guys!! (Math related) - 10/3/2008 12:59:20 PM

P360onBugs

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yeah. i bet im on the right track. i got most of the sections figured out. just one section is bothering me.

but you have to admit this one one of these problems that seems so dang simple till you actually start doing it.

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Post #: 117

RE: help guys!! (Math related) - 10/3/2008 2:02:54 PM

Big_T

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In real life a problem like this would be simplified by assuming straight lines instead of arcs.

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Post #: 118

RE: help guys!! (Math related) - 10/3/2008 3:12:40 PM

CodyD

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Or in real life if I had a round pen and I only wanted the cow to eat half of it I would put some cattle panels right down the middle.

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Post #: 119

RE: help guys!! (Math related) - 10/3/2008 3:18:35 PM

Scooped_Kawasaki

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I'm not even going to pretend I know how to figure out the problem but unless you take into account the extra length of the rope needed for the knots to tie it to the fence and around the animals neck then figure in the length of the animals neck from where the rope is tied all the way to it's teeth, your answer will be wrong.

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